Unit 2 — Whole Numbers
Sindh Textbook Board — Solved notes with verified answers
1. Key Concepts — Whole Numbers
- Natural numbers N = {1, 2, 3, 4, ...} — used for counting. 1 is the smallest natural number.
- Whole numbers W = {0, 1, 2, 3, 4, ...} — natural numbers together with 0. 0 is the smallest whole number.
- The only difference between N and W is the number “0” — 0 belongs to W but not to N.
- Predecessor = a number minus 1 (the number just before it). Successor = a number plus 1 (the number just after it). E.g. predecessor of 1 is 0; successor of 1 is 2.
- Number line: a line on which whole numbers are marked at equal distances. A number is bigger than any number on its left and smaller than any number on its right.
Laws of Whole Numbers
- Commutative law (addition): a + b = b + a e.g. 9 + 30 = 30 + 9
- Associative law (addition): (a + b) + c = a + (b + c) e.g. (3 + 7) + 12 = 3 + (7 + 12) = 22
- Additive identity: 0 — a + 0 = 0 + a = a
- Commutative law (multiplication): a × b = b × a e.g. 5 × 6 = 6 × 5 = 30
- Associative law (multiplication): (a × b) × c = a × (b × c) e.g. (3 × 2) × 4 = 3 × (2 × 4) = 24
- Multiplicative identity: 1 — a × 1 = 1 × a = a | a × 0 = 0
- Distributive law (over addition): a × (b + c) = a × b + a × c e.g. 2 × (4 + 7) = 2 × 4 + 2 × 7 = 22
- Distributive law (over subtraction): a × (b − c) = a × b − a × c e.g. 2 × (7 − 4) = 2 × 7 − 2 × 4 = 6
- Division: a whole number divided by 1 is the number itself; 0 divided by any non-zero whole number is 0; division by 0 is not defined.
2. Exercise 2.1 — Solved
| (i) 1 and 5 | → 1 + 5 = 6 |
| (ii) 6 and 3 | → 6 + 3 = 9 |
| (iii) 10 and 2 | → 10 + 2 = 12 |
| (iv) 8 and 4 | → 8 + 4 = 12 |
| (v) 2, 3 and 5 | → 2 + 3 + 5 = 10 |
| (vi) 3, 2 and 4 | → 3 + 2 + 4 = 9 |
Activity 1 (p. 125) — Fill in the blanks using Commutative and Associative laws of addition
3. Exercise 2.2 — Solved
Sum = 999999 + 1000000 = 1,999,999
| (i) 7628 and 39780 | 7628 + 39780 = 47408 = 39780 + 7628 ✓ |
| (ii) 924981 and 228 | 924981 + 228 = 925209 = 228 + 924981 ✓ |
| (iii) 29000 and 10699 | 29000 + 10699 = 39699 = 10699 + 29000 ✓ |
| (iv) 50102 and 9019854 | 50102 + 9019854 = 9069956 = 9019854 + 50102 ✓ |
| (i) 34006, 2389 and 44380 | (34006 + 2389) + 44380 = 80775 = 34006 + (2389 + 44380) ✓ |
| (ii) 583031, 127 and 3405 | (583031 + 127) + 3405 = 586563 = 583031 + (127 + 3405) ✓ |
| (iii) 231, 6090 and 25996 | (231 + 6090) + 25996 = 32317 = 231 + (6090 + 25996) ✓ |
| (iv) 412, 3007 and 102341 | (412 + 3007) + 102341 = 105760 = 412 + (3007 + 102341) ✓ |
Why: number → 2n → 2n + 9 → + n = 3n + 9 → ÷ 3 = n + 3 → − 3 = n
4. Exercise 2.3 — Solved
| (i) 854 × 96 | = 81984 |
| (ii) 736 × 103 | = 75808 |
| (iii) 256 × 1008 | = 258048 |
| (iv) 995 × 158 | = 157210 |
| (i) 7772 ÷ 58 | Quotient = 134, Remainder = 0 |
| (ii) 96324 ÷ 245 | Quotient = 393, Remainder = 39 |
| (iii) 16025 ÷ 1000 | Quotient = 16, Remainder = 25 |
| (iv) 92845 ÷ 300 | Quotient = 309, Remainder = 145 |
99999 − 24 = 99975 (99975 ÷ 75 = 1333)
5. Exercise 2.4 — Solved
(ii) 67 − (125 − 12) = (67 − 125) − 12 — False
(iii) 64 × (245 − 10) = 64 × 245 − 64 × 10 — True (distributive law)
(iv) 95 × (25 × 14) = (95 × 25) + 14 — False
Since LHS = RHS, commutative law under addition is verified.
| (i) 9 × 7 = 7 × 9 | Law: Commutative law under multiplication (63 = 63) |
| (ii) 4 × (6 × 3) = (4 × 6) × 3 | Law: Associative law under multiplication (72 = 72) |
| (iii) 5 × (7 − 1) = 5 × 7 − 5 × 1 | Law: Distributive law of multiplication over subtraction (30 = 30) |
| (iv) 2 × (8 + 3) = 2 × 8 + 2 × 3 | Law: Distributive law of multiplication over addition (22 = 22) |
RHS = 240 × (425 × 35) = 240 × 14875 = 3,570,000
Since LHS = RHS, associative law under multiplication is verified.
RHS = 300 × 615 + 300 × 975 = 184,500 + 292,500 = 477,000
Since LHS = RHS, distributive law is verified.
6. Review Exercise 2 — Solved
(ii) 3 × 1 + 7 = 3 × 8 — False (10 ≠ 24)
(iii) 2 − (0 − 8) = (2 − 0) + 8 — True (2 + 8 = 2 + 8)
(iv) 9 + (7 + 5) = (9 + 7) + 5 — True (associative law)
(v) 4 × (35 × 2) = (4 × 35) × 2 — True (associative law)
(vi) 24 − (50 − 6) = (24 − 50) − 6 — False (−20 ≠ −32)
(vii) 14 ÷ 0 = 14 — False (division by 0 is not defined)
(viii) 0 ÷ 125 = 0 — True
(ix) 18 ÷ 18 = 0 — False (18 ÷ 18 = 1)
(x) 75 ÷ 75 = 1 — True
(ii) 24 → e.g. 10 and 14
(iii) 31 → e.g. 15 and 16
Note: any pair of whole numbers adding to the given sum is correct.
Multiplication: 190 × 330 = 62700 = 330 × 190 ✓
Multiplication: (20 × 30) × 60 = 36000 = 20 × (30 × 60) ✓
700 × 500 + 700 × 100 = 350,000 + 70,000 = 420,000 ✓
Over subtraction: 700 × (500 − 100) = 700 × 400 = 280,000
700 × 500 − 700 × 100 = 350,000 − 70,000 = 280,000 ✓
9999 − 11 = 9988 (9988 ÷ 44 = 227, remainder 0)
7. Key Facts from the Summary (Book p. 135)
- Natural numbers N = {1, 2, 3, ...} are used for counting.
- Whole numbers W = {0, 1, 2, ...} = zero + all natural numbers.
- Sum and product of two whole numbers is also a whole number.
- Zero (0) is the additive identity; One (1) is the multiplicative identity.
- Addition and multiplication of whole numbers are commutative and associative.
- Multiplication is distributive over addition and subtraction (with positive difference).
- Division of two whole numbers gives a whole number only when the divisor divides exactly (remainder = 0).
Questions and answers verified against the ANSWER KEY of the Sindh Textbook Board (STBB) – Mathematics for Class 6, Unit 2: Whole Numbers (answer key on printed pp. 248–250 of the textbook).
Note: The workbook/guide (.doc) supplied for this unit is a scanned image file with no text layer, so it could not be extracted; all solutions above are worked out step-by-step and then cross-checked against the printed answer key. All checked answers agree with the key (e.g. products 81984 / 75808 / 258048 / 157210; quotients 134r0, 393r39, 16r25, 309r145; Rs 42,300; 715 children; 99975; 999900; Rs 1,227,500; 9988; Rs 960).
Answers that depend on choice (Review Q8 pairs) are given as examples only. Prepared for study & revision purpose only.


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